計算題
1、在額定輸出為5000千伏安,鐵耗為110千瓦,滿載銅耗為160千瓦的變壓器上,帶有1250千伏安的負(fù)荷,求這時變壓器的效率。假定負(fù)載的功率因素為0.9。
解:因鐵耗與負(fù)荷無關(guān),銅耗與負(fù)荷的平方成正比,所以該變壓器在帶1250千伏安的負(fù)荷時的總耗PΣ為
PΣ=110+160×(1250/5000)2=120(千瓦)
假定變壓器負(fù)荷為S'0,則其有功負(fù)荷為
P'0=S'0cosφ=1250×0.9=1125(千瓦)
此時變壓器的效率η為
η=P'0/P'0+P∑=1125/(1125+120)×100%=90.4%
答:該變壓器的效率為90.4%
2、一臺SFPL-120000/220變壓器,接線組別為Y0/Δ-11,額定電壓為220±2×2.5%/11KV。求一、二次繞組中的額定電流?
解:變壓器的額定電流
I1e=Se/
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0155.gif)
Ue=120000/
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0156.gif)
×220=314.9(A) I2e=Se/
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0157.gif)
U2e=120000/
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0158.gif)
×11=6298.4(A)
在一次側(cè),因Y形連接,故一次繞組中的額定電流
I1相=I1e=314.9(A)
在二次側(cè),因三角形連接,故二次繞組中的額定電流
I2相=I2e/
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0159.gif)
=6298.4/
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0160.gif)
=3636.4(A)
3、用一只內(nèi)阻為1800Ω,量程為150V的電壓表測量600V電壓,試求必須串接上多少歐姆的電阻?
解:設(shè)串接上的電阻為R
則150/1800=(600—150)/R
所以R=1800×(600—500)/150=5400(Ω)
答:串接5400Ω電阻。
4、一只電流表滿量限為10A,準(zhǔn)確等級為0.5,用此表測量1A電流時的相對誤差是多少?
解:最大相對誤差△m=0.5%×10=±0.05(A),測量1A的電流時,其相對誤差為±0.05/1×100%=±5%
5、已知某電源的相電壓Ux是6kV,如接成星形,它的線電壓是多少?已知UA=UmsinwtkV,寫出各相電壓,線電壓的瞬時表達(dá)式。
解:線電壓UL=
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0161.gif)
Ux=
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0162.gif)
×6(kV)
各相電壓,線電壓的瞬時值表達(dá)式為:
UA=UmsinwtkV
UB=Umsin(wt-120°)kV
UC=Umsin(wt+120°)kV
UAB=
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0163.gif)
Umsin(wt+30°)kV UBC=
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0164.gif)
Umsin(wt-90°)kV UCA=
![](file:///C:/Documents%20and%20Settings/Administrator/Application%20Data/Macromedia/Dreamweaver%208/OfficeImageTemp/clip_image002_0165.gif)
Umsin(wt+150°)kV
6、將一塊最大刻度是300A的電流表接入變比為300/5的電流互感器二次回路中,當(dāng)電流表指示為180A時,表計的線圈實際通過了多少電流?
解:
KL=I1/I2=300/5=60
I'2=I'1/K'L=180/60=3(A)
7、兩臺容量為63000kVA的變壓器的變比、接線組別均相同,阻抗電壓Uk1%=7,Uk2%=8,兩臺變壓器并列運行時輸出的總功率S=100000kVA,問兩臺變壓器各帶多少負(fù)荷?
解:
S1=(S1e/Uk1%)×[S/(S1e/Uk1%
+S2e/Uk2%)]
=(63000/7)×[100000/(63000/7
+63000/8)]=53333(kVA)
S2=S-S1=100000-53333=46667(kVA)
8、某一50HZ電動機旋轉(zhuǎn)磁場的轉(zhuǎn)數(shù)為1500轉(zhuǎn)/分,求該電動機的極數(shù)為多少?
解:根據(jù)公式:N1=(60*F1)/ρ
則ρ=(60*F1)/ N1=(60*50)/1500=2(極對)
則極數(shù):ρ*2=4(極)
答:該電動機的極數(shù)為4極。
9、某水電廠水輪機發(fā)電機組發(fā)電機極數(shù)為12,頻率為50HZ,求旋轉(zhuǎn)磁場的轉(zhuǎn)數(shù)為多少?
解:N1=(60*F1)/ρ=(60*50)/12/2=500轉(zhuǎn)/分
10、某異步電動機為2極對,接在50HZ的低壓線路上,轉(zhuǎn)差率為3%,求該電動機的轉(zhuǎn)數(shù)為多少?
解:n=n1(1-s)=(1-3%)(60×f)/ρ=3000/2×97%=1455(轉(zhuǎn)/分)
答:該電動機的轉(zhuǎn)數(shù)為1455轉(zhuǎn)/分。